Time - Yoyo #38
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Time - Yoyo #38
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CheezItMan
reviewed
Sep 1, 2020
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| # Time Complexity: O(1) | ||
| # Space Complexity: O(1) | ||
| def add_first(value) |
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| new_node = Node.new(value) | ||
| if @head.nil? | ||
| @head = new_node | ||
| else | ||
| new_node.next = @head | ||
| @head = new_node | ||
| end |
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This can be simplified as:
Suggested change
| new_node = Node.new(value) | |
| if @head.nil? | |
| @head = new_node | |
| else | |
| new_node.next = @head | |
| @head = new_node | |
| end | |
| @head = Node.new(value, @head) |
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| # Time Complexity: O(1) | ||
| # Space Complexity: O(1) | ||
| def search(value) |
| new_previous = current.next | ||
| new_current = new_previous.next | ||
| new_previous.next = current | ||
| current = new_current |
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Missingend
Suggested change
| current = new_current | |
| current = new_current | |
| end |
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| if @head.nil? | ||
| return nil | ||
| end | ||
| previous = @head | ||
| current = @head | ||
| until current.data == value || current.nil? | ||
| previous = current | ||
| current = current.next | ||
| end | ||
| previous.next == current.next |
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You also need a check here to see if value is at the head of the list.
Suggested change
| if @head.nil? | |
| return nil | |
| end | |
| previous = @head | |
| current = @head | |
| until current.data == value || current.nil? | |
| previous = current | |
| current = current.next | |
| end | |
| previous.next == current.next | |
| if @head.nil? | |
| return nil | |
| elsif @head.data == value | |
| @head = @head.next | |
| return | |
| end | |
| previous = @head | |
| current = @head | |
| until current.data == value || current.nil? | |
| previous = current | |
| current = current.next | |
| end | |
| previous.next == current.next |
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| # Time Complexity: O(n) | ||
| # Space Complexity: O(n) | ||
| def visit |
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👍 , but the space complexity is O(1) because you're not making a new list here.
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| # Time Complexity: O(n) | ||
| # Space Complexity: O(1) | ||
| def reverse |
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end
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| # Time Complexity: O(1) | ||
| # Space Complexity: O(1) | ||
| def get_first |
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| # Time Complexity: O(n) | ||
| # Space Complexity: O(1) | ||
| def add_last(value) |
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| # Time Complexity: O(1) | ||
| # Space Complexity: O(1) | ||
| def get_last |
There was a problem hiding this comment.
👍 , but the time complexity is O(n) since you're traveling to the end of the list.
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