Vera - Time #32
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Vera - Time #32
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CheezItMan
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Sep 1, 2020
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| # Time Complexity: O(n) | ||
| # Space Complexity: O(n) | ||
| def search(value) |
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The space complexity is O(1) because you're not creating a new list as this method runs.
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| # method to return the max value in the linked list | ||
| # returns the data value and not the node | ||
| def find_max |
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| # Time Complexity: O(n) | ||
| # Space Complexity: O(n) | ||
| def find_min |
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👍 , except the space complexity is O(1)
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| # Time Complexity: O(n) | ||
| # Space Complexity: O(n) | ||
| def length |
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| # Time Complexity: O(n) | ||
| # Space Complexity: O(n) | ||
| def get_at_index(index) |
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What if the length is <= index? You've got to do something to handle that edge case.
| return | ||
| end | ||
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| pointer = find_previous(value) |
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| # Time Complexity: O(n) | ||
| # Space Complexity: O(n) | ||
| def delete(value) | ||
| raise NotImplementedError |
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| # Time Complexity: O(1) | ||
| # Space Complexity: O(1) | ||
| def get_first |
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| # Time Complexity: O(1) | ||
| # Space Complexity: O(1) | ||
| def add_last(value) |
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👍 , however the time complexity is O(n) because you are traveling to the rear of the list.
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| # Time Complexity: O(n) | ||
| # Space Complexity: O(n) | ||
| def get_last |
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👍 , but the space complexity is O(1)
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