Find Target Indices After Sorting Array.cpp

/*
You are given a 0-indexed integer array nums and a target element target.

A target index is an index i such that nums[i] == target.

Return a list of the target indices of nums after sorting nums in non-decreasing order. If there are no target indices, return an empty list. The returned list must be sorted in increasing order.

 

Example 1:

Input: nums = [1,2,5,2,3], target = 2
Output: [1,2]
Explanation: After sorting, nums is [1,2,2,3,5].
The indices where nums[i] == 2 are 1 and 2.
Example 2:

Input: nums = [1,2,5,2,3], target = 3
Output: [3]
Explanation: After sorting, nums is [1,2,2,3,5].
The index where nums[i] == 3 is 3.
Example 3:

Input: nums = [1,2,5,2,3], target = 5
Output: [4]
Explanation: After sorting, nums is [1,2,2,3,5].
The index where nums[i] == 5 is 4.
 

Constraints:

1 <= nums.length <= 100
1 <= nums[i], target <= 100

*/


class Solution {
public:
    vector<int> targetIndices(vector<int>& nums, int target) {
        vector<int> res;
        sort(nums.begin(), nums.end());
        for(int i=0;i<nums.size();i++){
            if(nums[i] ==  target) res.push_back(i);
        }
        return res;
    }
};