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Copy path03. Consecutive Characters.cpp
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03. Consecutive Characters.cpp
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/*
Consecutive Characters
======================
Given a string s, the power of the string is the maximum length of a non-empty substring that contains only one unique character.
Return the power of the string.
Example 1:
Input: s = "leetcode"
Output: 2
Explanation: The substring "ee" is of length 2 with the character 'e' only.
Example 2:
Input: s = "abbcccddddeeeeedcba"
Output: 5
Explanation: The substring "eeeee" is of length 5 with the character 'e' only.
Example 3:
Input: s = "triplepillooooow"
Output: 5
Example 4:
Input: s = "hooraaaaaaaaaaay"
Output: 11
Example 5:
Input: s = "tourist"
Output: 1
Constraints:
1 <= s.length <= 500
s contains only lowercase English letters.
Hint #1
Keep an array power where power[i] is the maximum power of the i-th character.
Hint #2
The answer is max(power[i]).
*/
class Solution
{
public:
int maxPower(string s)
{
if (s.size() == 0)
return 0;
char prev = s[0];
int count = 1, ans = 1;
for (int i = 1; i < s.size(); ++i)
{
int curr = s[i];
if (curr == prev)
{
count++;
ans = max(ans, count);
}
else
{
prev = curr;
count = 1;
}
}
return ans;
}
};