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018-maximum-path-sum-I.lhs
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#!/usr/bin/env runhaskell
[Problem 18](http://projecteuler.net/problem=18)
By starting at the top of the triangle below and moving to adjacent numbers on
the row below, the maximum total from top to bottom is 23.
3
7 4
2 4 6
8 5 9 3
That is, 3 + 7 + 4 + 9 = 23.
Find the maximum total from top to bottom of the triangle below:
75
95 64
17 47 82
18 35 87 10
20 04 82 47 65
19 01 23 75 03 34
88 02 77 73 07 63 67
99 65 04 28 06 16 70 92
41 41 26 56 83 40 80 70 33
41 48 72 33 47 32 37 16 94 29
53 71 44 65 25 43 91 52 97 51 14
70 11 33 28 77 73 17 78 39 68 17 57
91 71 52 38 17 14 91 43 58 50 27 29 48
63 66 04 68 89 53 67 30 73 16 69 87 40 31
04 62 98 27 23 09 70 98 73 93 38 53 60 04 23
NOTE: As there are only 16384 routes, it is possible to solve this problem by
trying every route. However, Problem 67, is the same challenge with a triangle
containing one-hundred rows; it cannot be solved by brute force, and requires a
clever method! ;o)
Code
----
> triangle :: [[Int]]
> triangle = [[75]
> ,[95,64]
> ,[17,47,82]
> ,[18,35,87,10]
> ,[20,04,82,47,65]
> ,[19,01,23,75,03,34]
> ,[88,02,77,73,07,63,67]
> ,[99,65,04,28,06,16,70,92]
> ,[41,41,26,56,83,40,80,70,33]
> ,[41,48,72,33,47,32,37,16,94,29]
> ,[53,71,44,65,25,43,91,52,97,51,14]
> ,[70,11,33,28,77,73,17,78,39,68,17,57]
> ,[91,71,52,38,17,14,91,43,58,50,27,29,48]
> ,[63,66,04,68,89,53,67,30,73,16,69,87,40,31]
> ,[04,62,98,27,23,09,70,98,73,93,38,53,60,04,23]]
> step :: [Int] -> [Int] -> [Int]
> step lower higher = let maxs = zipWith max lower (tail lower)
> in zipWith (+) maxs higher
> main :: IO ()
> main = let result = head . foldl1 step $ reverse triangle
> in print result
Answer
------
1074