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On a p = c^d [n] avec c = M^e [n]

c_4 = 5^e [n]

On calcule C = cc_4 = (M^e)(5^e) = (5M)^e

Si on envoie C l'oracle nous retourne p = ((5M)^e)^d [n] = 5M

Le Flag est donc M/5

alt text

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